Solve by factorization method :::::
- x2 + 3x - (a2 + a - 2) = 0
- a2b2x2 + b2x - a2x - 1 = 0
- x2 + x - (a + 1)(a + 2) = 0
- x2 + ({a/a +b} + {a + b/a})
- 1/a+b+x = 1/a + 1/b + 1/x
Dear Student!
Here is the answer to your question.
1.
⇒ x2 + 3x – (a2 + a – 2) = 0
⇒ x2 + 3x – (a + 2) (a – 1) = 0
⇒ x2 + [(a + 2)] – (a – 1)] x – (a + 2) (a – 1) = 0
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⇒ –ab = x2 + ax + bx
⇒ x2 + ax + bx + ab = 0
⇒ x (x + a) + b (x + a) = 0
⇒ (x + b) (x + a) = 0
⇒ x + b = 0 or x + a = 0
⇒ x = – b or x = – a
Thus, the solutions of given quadratic equation are –a, –b.
Cheers!