Solve: dy/dx = 1 + x + y + xy Answer given in the book is : log | 1 + y| = x + 1/2 x2 + C Share with your friends Share 13 Vipin Verma answered this dydx = 1+x+y +xy⇒ dydx = (1+x)(1+y)⇒ dy1+y=(1+x)dx [variable seperable]Integrating both sides, we get∫ dy1+y = ∫(1+x)dx⇒ ln|1+y| =x+x22 +C 41 View Full Answer