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Let the digit at units place = x Digit at hundreds place = 4 x Now, let digit at tens place = y Now, original number = 100 \times 4 x + 10 \times y + x = 400 x + 10 y + x = 401 x + 10 y Now, according to first condition : x + 4 x + y = 14 \Rightarrow 5 x + y = 14 \Rightarrow y = 14 - 5 x . . . . . (1) Now, when the digits are reversed, then new number = 100 \times x + 10 \times y + 4 x = 104 x + 10 y Now, according to second condition : 104 x + 10 y + 594 = 401 x + 10 y \Rightarrow 297 x = 594 \Rightarrow x = 2 Now, from (1), we get y = 14 - 5 \times 2 = 14 - 10 = 4 Now, original number = 401 \times 2 + 10 \times 4 = 842

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