solve fast iv) log8log2×log3log3=2 logx - Maths - Indices and Logarithms

Question

solve fast
iv) log8 log2 × log 3 log 3 =2 logx

Abhishek Kr. Jha · Accepted Answer

Dear student,
Here is the solution of your asked query:
log8log2×log3log3=2logx⇒log23log2×log32log3=2logx⇒3log2log2×2log3log3=2logx                         {Since, logam=mloga}⇒3log2log2×2log3log3=2logx⇒3×2=2logx⇒logx=3Logx means that the base is 10 i
e
 log10x⇒log10x=3⇒x=103                            {since, logab=m then b=am}⇒x=1000
Regards

solve fast iv) log8 log2 × log 3 log 3 =2 logx.

solve fast
iv) $\frac{log8}{log2} × \frac{log 3}{log \sqrt{3}}$ =2 logx.