solve for: 37x+41y=70 41x+37y=86 Share with your friends Share 2 Amit Shukla answered this Dear Student, We have,37x+41y=70 ---(1)41x+37y=86 ---(2)Adding eqn (1) and (2), we get,78x+78y=15678x+y=156x+y=5678x+y=2---(3)Now subtracting eqn (1) from eqn (2) we get,-4x+4y=-16-4x-y=-16x-y=4 ---(4)Now adding eqn (3) and (4), we get;2x=6x=3,Now in eqn (3),3+y=2y=2-3 =-1Therefore,x=3 and y=-1 Regards 2 View Full Answer
