# solve for x 1+4x+1+6x= 1+2x+3+4

Dear student
$1+4\mathrm{x}+1+6\mathrm{x}=1+2\mathrm{x}+3+4\phantom{\rule{0ex}{0ex}}⇒2+10\mathrm{x}=2\mathrm{x}+8\phantom{\rule{0ex}{0ex}}⇒10\mathrm{x}-2\mathrm{x}=8-2\phantom{\rule{0ex}{0ex}}⇒8\mathrm{x}=6\phantom{\rule{0ex}{0ex}}⇒\mathrm{x}=\frac{3}{4}$
Regards

• 0
10x + 2 = 2x + 8
10x - 2x = 8 - 2
8x = 6
x = 6
8
x = 3
4

• -2
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• -1
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