Solve for x : 9 x2 -9(a+b) x+ 2 a^2+5 ab+ 2 b^2= 0........I need handwritten answer....

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Using x=-b+/- √(b^2-4ac)/2a, we get x= 9(a+b)+/- √81(a+b)^236(2a^2+5ab+2b°2)/2*9 = 9(a+b)+/- √{9a^2+9b^2-18ab)/18 = 9(a+b)+/- 3√{{a-b)^2/18 = 9(a+b)+/- 3(a-b)/18= 3(a+b)+/- (a-b}/6 So x= (2a+b)/3, OR (a+2b)/3
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