Solve it asap on a paper

Dear Student,
Arrheniusequation is given by,

Thegiven equation is

Fromequation (i)and (ii), we obtain

= 1.25 ×10⁴K × 2.303 × 8.314 J K⁻¹mol⁻¹

= 239339.3 Jmol⁻1(approximately)

= 239.34 kJmol⁻¹

Also,when t_1/2= 256 minutes,

=2.707 × 10⁻³min⁻¹

=4.51 × 10⁻⁵s⁻¹

Itis also given that, log k= 14.34 − 1.25 × 10⁴K/T

=668.95 K

=669 K (approximately)

Regards,