Solve it now

Solve it now (i) 4. A solid body weighs 2•10 N in air. Its relative density is 8•4. How much will the body weigh if placed (i) in water, (ii) in a liquid of relative density ? Given : Weight of the body in air WI = 2•10

Dear student

Weight in air = 2.10 N

R.D = 8.4 

i) RD = weight of body in Air/upthrust

Therefore,

Upthrust = weight of body in air/ RD  = 2.10/8.4 = 0.25
Therefore, 

Weight of the body in water = 2.10 – 0.25 = 1.85 N

ii) 

R.D = loss of wt in liquid / loss of weight in water
 

Loss of weight in liquid = RD x loss of weight in water 

                                 = 1.2 x 0.25 

                                 = 1.85 N

Therefore, weight of the body in liquid = 2.1 – 0.3 

                                                        = 1.8 N

Regards