cos 65°sin 25° + cos 32°sin 58° - sin 28° sec 62° + cosec230°=cos90°-25°sin 25° + cos90°-58°sin 58° - sin 90°-62° sec 62°+ 22=sin 25°sin 25° + sin 58°sin 58° - cos 62° sec 62° + 4=1 + 1 - cos 62° × 1cos 62° + 4=2 - 1 + 4=5Using :cos90°-x = sin xsin90°-x = cos xsec x = 1cos xcosec 30° = 2

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\frac{\cos 65 °}{\sin 25 °} + \frac{\cos 32 °}{\sin 58 °} - \sin 28 ° . \sec 62 ° + {cosec}^{2} 30 ° = \frac{\cos (90 ° - 25 °)}{\sin 25 °} + \frac{\cos (90 ° - 58 °)}{\sin 58 °} - \sin (90 ° - 62 °) . \sec 62 ° + {(2)}^{2} = \frac{\sin 25 °}{\sin 25 °} + \frac{\sin 58 °}{\sin 58 °} - \cos 62 ° . \sec 62 ° + 4 = 1 + 1 - \cos 62 ° \times \frac{1}{\cos 62 °} + 4 = 2 - 1 + 4 = 5 Using : \cos (90 ° - x) = \sin x \sin (90 ° - x) = \cos x \sec x = \frac{1}{\cos x} cosec 30 ° = 2

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