Solve it please Number of digits in integral part of 6012 + 60–12 – 60–15 is (g) (A) 20 (B) 21 (C) 22 (D) 24 Share with your friends Share 0 Vishal Meena answered this Dear studentas 60-12 and 60-15 will no have integral part so we can remove them and now by taking log in the base of 10log106012=12log1060=12×1.778=21.336now number of digits will be =21+1hence ans is =22regards 0 View Full Answer