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Q.31. The volume occupied by 1.8 g H 2 O   a t   4 ° C and 760 mm pressure is
(a) 1.8 l
(b) 1.8 ml
(c) 2.27 l
(d) 2.98 ml

pV= nRTpV=wMRTV=wRTMpw= Weight = 1.8 gR= Gas constant = 0.0821 L atm/K/molT= Temperature = 273 +4 = 277 KM= Molecular weight of water = 18p = pressure = 760 mm = 1 atm V =1.8 ×0.0821×27718× 1 =2.27 L Thus option c is correct 

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