Solve : (k+4)x²+(k+1)x +1=0 has equal roots . Find the value of k.

(k+4)x²+(k+1)x+1=0

D=b²-4ac

=(k+1)2-4(k+4)(1)

=k²+2k+1-4k-16

=k²-2k-15

For equal roots, D=0

D=0

K²-2k-15=0

k²-5k+3k-15=0

k(k-5)+3(k-5)=0

(k+3)(k-5)=0

k+3=0 OR k-5=0

k=-3 , k=5