Solve no. 1 Share with your friends Share 0 Vipra Mishra answered this Dear Student As gievna α ta = ktk is constanta=dvdt= kt∫dv =∫ kt dtv=kt22+CAt t = 0 , speed of particle is = 0, so C = 0So t = nv=kn22Nowv = dxdt =kt22dx = kt22 dt∫dx =∫kt22 dtx =kt33×2+CAt t =0, x = 0 so C= 0x =kt36At t = nx =kn36 Regards 0 View Full Answer