Dear student,2 x=2134 12435 247x=2134 12413512 2417 [an=a1n]log x= log 2134 12413512 2417 log x= log 2134+log 12413-log 512-log 2417log x=34 log 21+13 log 124-12 log 5-17 log 24log x=34 log (3×7)+13 log (22×31)-12 log 5-17 log 23×3log x=34 log 3+34 log 7+13 log 22+13 log 31-12 log 5-17 log 23-17 log 3log x=34 log 3+34 log 7+23 log 2+13 log 31-12 log 5-37 log 2-17 log 3→log am=m log a→log ab = log a + log b→log ab=log a - log bRegards

Solve part 2 of this

D e a r s t u d e n t, 2 . x = \frac{21^{\frac{3}{4}} . \sqrt[3]{124}}{\sqrt{5} . \sqrt[7]{24}} x = \frac{21^{\frac{3}{4}} . 124^{\frac{1}{3}}}{5^{\frac{1}{2}} . 24^{\frac{1}{7}}} [\sqrt[n]{a} = a^{\frac{1}{n}}] \log x = \log (\frac{21^{\frac{3}{4}} . 124^{\frac{1}{3}}}{5^{\frac{1}{2}} . 24^{\frac{1}{7}}}) \log x = \log 21^{\frac{3}{4}} + \log 124^{\frac{1}{3}} - \log 5^{\frac{1}{2}} - \log 24^{\frac{1}{7}} \log x = \frac{3}{4} \log 21 + \frac{1}{3} \log 124 - \frac{1}{2} \log 5 - \frac{1}{7} \log 24 \log x = \frac{3}{4} \log (3 \times 7) + \frac{1}{3} \log (2^{2} \times 31) - \frac{1}{2} \log 5 - \frac{1}{7} \log (2^{3} \times 3) \log x = \frac{3}{4} \log 3 + \frac{3}{4} \log 7 + \frac{1}{3} \log 2^{2} + \frac{1}{3} \log 31 - \frac{1}{2} \log 5 - \frac{1}{7} \log 2^{3} - \frac{1}{7} \log 3 \log x = \frac{3}{4} \log 3 + \frac{3}{4} \log 7 + \frac{2}{3} \log 2 + \frac{1}{3} \log 31 - \frac{1}{2} \log 5 - \frac{3}{7} \log 2 - \frac{1}{7} \log 3 \to \log a^{m} = m \log a \to \log a b = \log a + \log b \to \log \frac{a}{b} = \log a - \log b R e g a r d s

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