Dear student, We have,E-E-E-E-E-A=E-E-E-A [using E-E-A=A]=E-A [using E-E-A=A]=E-B∪C=B∪C'By Demorgan's law=B'∩C'thus option c is correct Regards

Solve plzz

Dear student,

W e h a v e, E - (E - (E - (E - (E - A)))) = E - (E - (E - A)) . . . [u \sin g (E - (E - A)) = A] = E - A . . . [u \sin g (E - (E - A)) = A] = E - (B \cup C) = (B \cup C)' B y D e m o r g a n' s l a w = B' \cap C' t h u s o p t i o n c i s c o r r e c t

Regards