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solve

Q.52. The partial pressures of ${N}_{2},{O}_{2}andC{O}_{2}$ in a vessel are 38 cm of Hg, 190 torr and 0.5 atm, respectively. The total pressure of the mixture at the same temperature is

(a) 0.96 atm

(b) 1.02 atm

(c) 1.64 atm

(d) 1.25 atm

1 atm = 76cm of Hg = 760 torr

Total Pressure is sum of individual partial pressures of all the gases.

Hence

${P}_{total}={P}_{{N}_{2}}+{P}_{{O}_{2}}+{P}_{C{O}_{2}}$

${P}_{total}=\left(\frac{38}{76}\right)+\left(\frac{190}{760}\right)+0.5atm\phantom{\rule{0ex}{0ex}}{P}_{total}=1.25atm\phantom{\rule{0ex}{0ex}}$

Hope this helps,

Regards

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