solve Q 8 (plz dont give link)
Given: Mass of BaCl2.8H2O = 10.56 g
Volume of solution = 1 L
To find: Concentration of chloride ion in molarity
Solve: Molar mass of BaCl2.8H2O = 137.327 +(235.5) + 818
= 352.327 g mol-1
Number of moles = mass / molar mass
= 10.56 / 352.327
= 0.03 moles
Molarity = Number of moles / Volume of solution
= 0.03 / 1
= 0.03 M
1 M of BaCl2.8H2O contains 2 M chloride ions.
So, 0.03 M of BaCl2.8H2O contains 20.03 M of chloride ions
=0.06 M of chloride ions
Concentration of chloride ion is 0.06 M
Volume of solution = 1 L
To find: Concentration of chloride ion in molarity
Solve: Molar mass of BaCl2.8H2O = 137.327 +(235.5) + 818
= 352.327 g mol-1
Number of moles = mass / molar mass
= 10.56 / 352.327
= 0.03 moles
Molarity = Number of moles / Volume of solution
= 0.03 / 1
= 0.03 M
1 M of BaCl2.8H2O contains 2 M chloride ions.
So, 0.03 M of BaCl2.8H2O contains 20.03 M of chloride ions
=0.06 M of chloride ions
Concentration of chloride ion is 0.06 M