# Solve question 1010. A ray incident at an angle 53$°$ on a prism emerges at an angle at 37$°$ as shown. If the angle of incidence is made 50$°$, which of the following is a possible value of the angle of  emergence.  (A)  35$°$                   (B)  42$°$                       (C)  40$°$                            (D)   38$°$

According to Prism law
i + e = A + d (d is angle of deviation)
In the first case, i +e =90 (53+37)
Hence A+d=90
d is a characteristic of the corresponding wavelength of light in the material of prism of some refractive index.
Since here we are using the same light wave, the d remains constant. is the Angle of Prism and is constant.
Thus A+d remains constant. SInce its initial value was 90, its final value will be 90 too.
Thus according to Prism Law
i+e should be equal to A+d thus equal to 90
In second case, i=50
i+e=90
e=90-50
e=40

• 1
According to Prism law
i + e = A + d (d is angle of deviation)
In the first case, i +e =90 (53+37)
Hence A+d=90
d is a characteristic of the corresponding wavelength of light in the material of prism of some refractive index.
Since here we are using the same light wave, the d remains constant. is the Angle of Prism and is constant.
Thus A+d remains constant. SInce its initial value was 90, its final value will be 90 too.
Thus according to Prism Law
i+e should be equal to A+d thus equal to 90
In second case, i=50
i+e=90
e=90-50
e=40
This should be the angle of emergence.
• 0
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