Q.11) In triangle COA and triangle POB,
CO = PO (As O is the bisector of the line)
AO = BO (As O is the bisector of the line)
Angle COA = Angle POB (Vertically opposite angles are equal)
By SAS congruency triangle COA is congruent to triangle POB,
i) By CPCT,
AC = BD
ii) By CPCT,
Angle CAB = Angle ABD
iii) In Quadrilateral CBAD,
As Angle CAB = Angle ABD
Alternate interior angles are equal, and they only equal if the two lines are parallel,
AC || BD
iv) In triangle COB and triangle POA,
CO = PO (As O is the bisector of the line)
AO = BO (As O is the bisector of the line)
Angle AOP = Angle BOC (Vertically opposite angles are equal)
By SAS congruency triangle COB congruent to triangle POA,
By CPCT,
AD = CB
Whew! This answer took a long time to write!
