Solve question 4 4 . L im x → 0 27 x - 9 x - 3 x + 1 2 - 1 + cos x ( A ) 4 2 ln 3 2 ( B ) 8 2 ( ln 3 ) 2 ( C ) 4 2 ln 3 ( D ) 8 2 ln 3 Share with your friends Share 0 Aarushi Mishra answered this limx→027x-9x-3x+12-1+cos xlimx→027x-9x-3x+12-1+cos xlimx→09x3x-1-3x+12-1+cos xlimx→09x3x-1-3x-12-1+cos xlimx→03x-19x-12-2 cos2xlimx→03x-19x-12-2 cos2x×2+2 cos2x2+2 cos2xlimx→03x-19x-122-2 cos2x22+2 cos2xlimx→03x-19x-12-2cos2x2+2 cos2xlimx→03x-19x-121-cos2x2+2 cos2xlimx→03x-19x-12+2 cos2x2sin2xlimx→03x-19x-12sin2xlimx→02+2 cos2xlimx→03x-1x9x-1x2sin2xx2limx→02+2 cos2xlimx→03x-1xlimx→09x-1x2limx→0sinxx22+2 limx→03x-1xlimx→09x-1x2limx→0sinxx222Use limx→0ax-1x=ln a and limx→0sinxx=1=2ln 32 ln 3Use logabm=m logab=22ln 3 ln 3=2ln 32 Please check the options 0 View Full Answer