Solve question no.8 Share with your friends Share 0 Priyanka Sahu answered this Dear Student Since ABCD is a parallelogram, then AB = CD and AD = BC, as opposite sides of ∥gm are equal.Now, AB = CDSince, E is mid point of AB and F is the mid point of CD, thenAE = BE = CF = DF.In ∆HBE and ∆HFC∠EHB = ∠FHC Vertically opposite angles∠HBE = ∠HFC Alternate interior angles as AB∥CD and BF is a transversalBE = CF Proved above∆HBE ≅ ∆HFC AASIn Quadrilateral AECF,AE = CF proved aboveAE∥CF as AB∥DC⇒AECF is a ∥gm in a quad, if a pair of opposite sides is equal and ∥, then it is a ∥gm ⇒EC∥AF or EH∥GF ....1In Quadrilateral BFDE,BE = DF proved aboveBE∥DF as AB∥DC ⇒BEDF is a ∥gm in a quad, if a pair of opposite sides is equal and ∥, then it is a ∥gm ⇒BF∥ED or HF∥EG .....2from 1 and 2, we getHFGE is a parallelogram Regards 0 View Full Answer
