Solve qus no. 6
Q.6. To obtain 2.70 g of silver (at. mass 108) from an aqueous solution of A g N O 3 it is required to pass
A. 4750 coulomb
B. 12062 coulomb
C. 2412.5 coulomb
D. 241.5 coulomb

Dear student ,
as we know that ; Ag+  + 1e-  =  Ag (1 mol or 108 gm)
      and we also know that 1 mol e- carry 1 F (96500 C) 
therefore ; it is given above that 108 gm Ag deposit by 1F 
                               therefore 2.70 gm Ag requires 0.025 F or 2412.5 C
  option C is correct
  Regards
 

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for 108 grams ---> 96500
for 2.7 grams----> 2412.5
by cross multiplication
ans - C
  • 1
2412.5 
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