solve : sin 3 theta + cos 2 theta = 0 its urgent tomorrow is exam Share with your friends Share 4 Varun.Rawat answered this sin 3θ + cos 2θ = 0⇒cos 2θ = - sin 3θ⇒cos 2θ = cosπ2+3θ⇒2θ = 2nπ±π2+3θ , where n∈I⇒θ = -2nπ-π2 or 5θ = 2nπ-π2⇒θ = 2nπ-π2 or θ = 2nπ5-π10 , where n∈IAs, -2nπ-π2 and 2nπ-π2 will give same result for n ∈ I. 23 View Full Answer Utkarsh answered this sin theta is 45 degree and 60 degree -21