solve : sin 3 theta + cos 2 theta = 0
its urgent tomorrow is exam

sin 3θ + cos 2θ = 0cos 2θ = - sin 3θcos 2θ = cosπ2+3θ2θ = 2±π2+3θ , where nIθ = -2-π2    or  5θ = 2-π2θ = 2-π2    or  θ = 25-π10 , where  nIAs, -2-π2 and 2-π2 will give same result for n  I.

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sin theta is 45 degree and 60 degree
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