Solve the 16

$\frac{2}{\mathrm{x}}+\frac{2}{3\mathrm{y}}=\frac{1}{6},\frac{3}{\mathrm{x}}+\frac{2}{\mathrm{y}}=0$

Dear Student,

Let 1/x be u and 1/y be v
Therefore,
2u + 2v/3 = 1/6 ...(i)

And

3u + 2v = 0 ...(ii) 

Subtracting 2/3 x(ii) from (i)
we have,

2u + 2v/3 = 1/6
-2u - 4v/3 = 0

Or, -2v/3 = 1/6
Or, -v = 1/4

v = -1/4

Substituting value of v in equation (ii) , we have

3u + 2v = 0
Or, 3u + 2(-1/4) = 0
Or, 3u -1/2 = 0
Or, u = 1/6

Therefore, 

1​/x = u = 1/6
so, x = 6
And,

1/y = v = -1/4
So, y = -4

I hope you understood the solution

Regards
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