Solve the 2nd part of 36.4

Dear Student,

E q u a t i o n o f l i n e, \frac{x - 2}{2} = \frac{z - 3}{3} = \frac{y + 2}{1} a n d l i n e - 2 x + 4 y - 5 z = 20 d i r e c t i o n r a t i o o f l i n e a r e l, m, n \Rightarrow 2, 1, 3 a n d a, b, c \Rightarrow - 2, 4, - 5 n o w \sin θ = \frac{l a + m b + n c}{\sqrt{l^{2} + m^{2} + n^{2}} \sqrt{a^{2} + b^{2} + c^{2}}} = \frac{2 \times - 2 + 1 \times 4 + 3 \times - 5}{\sqrt{2^{2} + 1^{2} + 3^{2}} \sqrt{(- 2)^{2} + 4^{2} + (- 5)^{2}}} = \frac{- 15}{\sqrt{14 \times 45}} = \frac{\sqrt{70}}{14} \sin θ = \frac{- 15}{\sqrt{14 \times 45}} = - \frac{\sqrt{70}}{14} = \frac{\sqrt{14 \times 5}}{\sqrt{14 \times 14}} = - \frac{\sqrt{5}}{\sqrt{14}} θ = - \sin^{- 1} (\frac{\sqrt{5}}{\sqrt{14}})

Regards.