Solve the encircled question

Dear student

W e h a v e \tan^{2} θ - \sin^{2} θ = \tan^{2} θ (1 - \cos^{2} θ) [A s \tan^{2} A \cos^{2} A = \sin^{2} A] = \tan^{2} θ \sin^{2} θ

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