Solve the equation: 2 sin^2 x = 3 cos x Share with your friends Share 3 Aman Rajput answered this Dear Student 2sin2x=3cos x⇒2-2cos2x-3cos x = 0⇒2 cos2x + 3 cos x - 2 = 0⇒2 cos2x + 4 cos x - cos x - 2 = 0⇒2 cos xcos x + 2 - 1cos x + 2 = 0⇒(2cosx-1)(cosx+2)=0⇒2 cos x - 1 = 0 or cos x + 2 = 0⇒cos x =12 or cos x = -2 rejected⇒cos x=cosπ3⇒x=2nπ±π3 , n∈Z Regards 31 View Full Answer