Solve the following pair of linear equation by elimination method x / 3 - 2y = 4 x + y/3 = 7 Share with your friends Share 0 Manbar Singh answered this The given equations are : x3 - 2y = 4⇒x - 6y3 = 4⇒x - 6y = 12 .....1and x + y3 = 7⇒3x + y3 = 7⇒3x + y = 21 ......2multiply 2 with 6 , we get18x + 6y = 126 ........3adding 1 and 3, we getx - 6y + 18x + 6y = 12 + 126⇒19x = 138⇒x = 13819 putting the value of x in 1, we get13819 - 6y = 12⇒-6y = 12 - 13819⇒-6y = 228 - 13819⇒- 6y = 9019⇒y = - 1519so, x = 13819 and y = -1519 is the solution. 1 View Full Answer Pranshu answered this x/3 - 2y = 4So, x - 6y =12 .........1And x+y/3 = 7So, 3x + y =21.........2Multiplying th first equation by 3 and then subtracting both 2 from 13x-18y = 363x +y = 21-19y = 15, y =-15/19Got this answer from edcoogle.com 2
