Solve the following question:-
​At 6 O' clock in the morning, a train leaves Damanjodi for Rourkela whlie another train leaves Rourkela for Damanjodi at the same time. It takes one train 8 hours and the other train 22 hours to make the trip. ​Both maintain a constant speed, at what time do they cross each other? 

​{Please try to avoid the providing of web-link and certified answer … I want only experts to their solutions. }

Dear Student,


Let distance between Damanjodi and Rourkela be x kmspeed of train A from damanjodi to rourkela=x8 km/hrspeed of train B from rourkela to damjodi=x22 km/hrThe relative speed when two trains running towards each other=speed of A +speed of BThe time at which trains cross each other=Total distancerelative speed=xx8+x22=x11x+4x88=88x15x=8815 hours=5+1315 hoursHence it is 5 hours +1315 hoursconvert 1315 hours to minutes by multiplying with 60=1315×60=52 minuteHence they meet after 5 hours 52 minuteas they started at 6 O' clock, they will meet at6+5 hours 52 minute=11:52 AM 
Regards,

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