Solve the given question :

Dear Student,

We know,
​​​​​​Linear momentum = mv

​Here, the 'v' can be calculated using the formula, $\nu =\sqrt{\frac{3RT}{M_m}}$

Here, M_m is the molar mass of the gas in Kg mol^-1.

So, the linear momentum is
 $$\begin{gathered} =\frac{166}{3}\times {10}^{-27}Kg\times \sqrt{\frac{3\times {\displaystyle \raisebox{1ex}{$25$}\!\left/ \!\raisebox{-1ex}{$3$}\right.} Jmo{l}^{-1}{K}^{-1}\times 150 K}{4\times {10}^{-3} Kg mo{l}^{-1}}} \\ =55.33\times {10}^{-27}\times 0.9682 \\ =53.57\times {10}^{-27} Kgm{s}^{-1} \end{gathered}$$


Regards