Solve the inequality I)log1/2(x) + log3(x) >1 II)log1/5(2x^2+5x+1) III)logx(2).log2x(2).log2(4x) >1 Share with your friends Share 1 Anuradha Sharma answered this Dear Student,log12x+log3 x>1-log2x+log3 x>1log3 x>1+log2xlog3 x>log22+log2x>log22xlog3 x>log22xlog xlog3>log2xlog2We know that log3>log2 so 1log3<1log2So logx must be grater than log2x logx>log2xBut here we cannot define value of x . Regards -6 View Full Answer
