Solve the problem:
11. Sum of the areas of two squares is 468 m2. If the difference in their perimeters is 24 m, find the sides of the two squares.
The measure of side of a square is a non-negative quantity.
Thus, the measure of sides of the smaller square is 12 m and the measure of sides of the larger square is 18 m (= 12 m + 6 m).