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a-bx+a+by=2a2-2b2Use formula a2-b2=(a-b)(a+b)a-bx=2a-ba+b-a+byx=2a+b-a+ba-by...1a+bx+y=4ab,....2Put x value from 12a+b-a+ba-by+y=4aba+by-a+ba-by=4aba+b-2a+by1-a+ba-b=4ab-2a+b2a+b[Using (a+b)2=a2+b2+2ab]ya-b-a-ba-b=4ab-2a2-2b2-4aba+by-2ba-b = -2a2+b2a+by = (a-b)(a2+b2)b(a+b)Put y value in equ. 1x = 2a+b-a+ba-b×(a-b)(a2+b2)b(a+b)x = 2a+b-a2+b2bx = 2ba+b-a2+b2bx = 2ab+2b2-a2-b2bx = 2ab+b2-a2b

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(a-b) x + (a+b)y = 2a² -2b²

(a-b) x + (a+b)y = (2a² -2b²)  ......(1)

(a + b ) (x+ y ) = 4ab

(a + b ) x +(a + b ) y = 4ab ......(2)

Now, by cross multiplication method

subtract the equation (2) from (1)

(a-b) x + (a+b)y = (2a² -2b²)  

(a + b ) x +(a + b ) y = 4ab

= -2bx  = (2a² -2b²)   - 4ab

bx =  (2a² -2b²)   - 4ab /-2

bx = a² + b² - 2ab

bx = a² - b²

x=  a² - b² /b

Substituting the value of (3) in equation 2

 

(a + b ) x +(a + b ) y = 4ab

(a + b )  a² - b² /b +(a + b ) y = 4ab

(a + b )(a + b )(a - b )/ b +(a + b )y = 4ab

y = 4ab ² / a³- b³ + a + b

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