Dear Student At Normal temperature pressure pressure is = 1 atm P1 =1 atm V1=224cm3 P2= ? V2= 224+(0 25*224)= 280 cm3 Now we know P1V1=P2V2 1*224 = P2 *280 P2=224/280 =0 8 atm Thus new pressure of the gas will be 0 8 atm 1 atm = 760 00 mmHg 0 8 × 760 = 608 mmHg Regards

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Dear Student

At Normal temperature pressure pressure is = 1 atm
P₁ =1 atm
V₁=224cm³
P₂= ?
V₂= 224+(0.25*224)= 280 cm3

Now we know
P₁V₁=P₂V₂

1*224 = P₂ *280
P₂=224/280 =0.8 atm
Thus new pressure of the gas will be 0.8 atm

1 atm = 760.00 mmHg

0.8 × 760 = 608 mmHg

Regards

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