Solve this 1. Calculate pH of mixture 200 mL of 0.2 M H2SO4 + 300 mL of 0.2 M NaOH + 200mL of 0.1 M KOH. Ans. 7 2. Calculate the pH when 200 mL of 0.25 M H2SO4 is mixed with 200 mL of 0.2 M Ba(OH)2 . Share with your friends Share 13 Geetha answered this 1. First find the miiliequivalent of acid and base200 mL of 0.2 M H2SO4 = Volume × molarity × n factor = 200 × 0.2 × 2 = 80 300 mL of 0.2 M NaOH + 200mL of 0.1 M KOH = 300 × 0.2 ×1 + 200 × 0.1 × 1 =80Since both acid and base have same equivalent they get neutralised.So the pH= 7, neutral one. 2. 200 mL of 0.25 M H2SO4 = Volume × molarity × n factor = 200 × 0.25 × 2 = 100200 mL of 0.2 M Ba(OH)2 =200 × 0.2 × 2 = 80Thus the resulting solution is more acidic by 100-80 = 20 milli equivalent. Molarity = 20Total volume of the solution = 20400 = 0.05 = 5 × 10-2pH= -log [H+] = - log 5 × 10-2 = 2- 0.6990 = 1.301 4 View Full Answer
