Solve this: 1 . Let f xy = f x f y V x , y ∈ R and f is differentiable at x = 1 such that f 1 = 1 also f 1 ≠ 0 , then show that is differentiable for all x ≠ 0 . Hence , determine f x . Share with your friends Share 0 Lovina Kansal answered this Dear student Givne: f(xy)=f(x)f(y)We know, f'(x)=limh→0f(x+h)-f(x)h⇒f'(x)=limh→0fx1+hx-f(x.1)h⇒f'(x)=limh→0f(x)f1+hx-f(x)f(1)h [using given relation]⇒f'(x)=limh→0f(x)f1+hx-f(1)h⇒f'(x)=limh→0f(x)x×f1+hx-f(1)hx⇒f'(x)=f(x)x f'(1)⇒f'(x)=f(x)x ∵f'(1)=1 given⇒f'(x)f(x)=1xIntegrating both sides, we get∫f'(x)f(x)=∫1x⇒logf(x)=logx+logC⇒f(x)=xC ...(1)Putting x=1=y in the given relation we findf(1)=f(1)f(1)⇒f(1)=1Putting x=1 in (1), we getf(1)=C⇒C=1SO, (1) becomesf(x)=x Regards 0 View Full Answer