Solve this:
10. In the adjoining figure, AD, BE and CF are altitudes of ABC. If AD = BE = CF, prove that ABC is an equilateral triangle.
Dear Meezan
As Per Your Given Image AD, BE and CF are altitudes of △ABC. If AD = BE = CF,
We have triangle ABE and triangle ACF
BE=CF (Given )
∠A=∠A (Common Angle )
∠AEB=∠AFC=90°
By congruent rule ABE ≅ ACF
AB=AC
Similarly
BCF ≅ ABD
AB=BC
AC=BC
AB=AC
AB = BC = AC
That means ABC is equilateral triangle .
Regards
As Per Your Given Image AD, BE and CF are altitudes of △ABC. If AD = BE = CF,
We have triangle ABE and triangle ACF
BE=CF (Given )
∠A=∠A (Common Angle )
∠AEB=∠AFC=90°
By congruent rule ABE ≅ ACF
AB=AC
Similarly
BCF ≅ ABD
AB=BC
AC=BC
AB=AC
AB = BC = AC
That means ABC is equilateral triangle .
Regards