Solve this:

10.
  ​In the adjoining figure, AD, BE and CF are altitudes of  ABC. If AD = BE = CF, prove that ABC is an equilateral triangle. 

Dear Meezan

As Per Your Given Image AD, BE and CF are altitudes of △ABC. If AD = BE = CF, 
We have ​​​​​ triangle ABE and triangle ACF 
BE=CF (Given ) 
∠A=∠A (Common Angle )
∠AEB=∠AFC=90° 
By congruent rule ABE ≅ ACF
AB=AC 
Similarly
BCF ≅ ABD
AB=BC
AC=BC
AB=AC
AB = BC = AC
That means ABC is equilateral triangle .

Regards


 

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