Solve this: 10 litre of an alkane X require 35 litre of 02 for complete combustion. X forms only one monochloro derivative Y. The action of alcoholic KOH on Y yields (1) CH3CH2CH20H (2) CH2 = CH2 (3) CH3CH = CH2 (4) CH3 -CH -CH3 OH Share with your friends Share 7 Vartika Jain answered this Dear Student, Only one monochloro derivative is formed which shows that the alkane has only one type of hydrogen.Also, action of alcohol KOH will give alkene as dehydrohalogenation will occur. So, correct option must be (2) or (3)(3) has two type of hydrogen, therefore the answer should be (2)CH3-CH3 →Cl2 CH3CH2Cl →alc. KOH CH2=CH2 (X) (Y) 7 View Full Answer
