Solve this:
12. In given figure 12, if ABC= BAD and BC=AD. Prove that AC=BD.
Hello Sruti, in triangle ABC and BAD,
AB is common
BC = AD
<BAD = <ABC
By SAS we can say triangle ABC ≡ triangle BAD
So AC = BD (opposite sides to equal angles)
Hence proved
AB is common
BC = AD
<BAD = <ABC
By SAS we can say triangle ABC ≡ triangle BAD
So AC = BD (opposite sides to equal angles)
Hence proved