Solve this:

122 .   2 x + 2 x 2 2 . 123 .   0 . 2 2 x - 3 x - 2 > 5 . 124 .   1 5 2 x + 1 1 - x > 1 5 - 3

 

Dear student
Since you have not mentioned the question number , so doing as per my knowledge.
We have,logx-13=2log3logx-1=2log3=2logx-1logx-1=log32logx-1=logelog32     as logeθ=θWhen logs have same bases i.e.  logbfx=logbgxfx=gxx-1=elog32x=elog32+1
Please post remaining queries in one thread.
Regards

  • 0
What are you looking for?