Solve this: 168 In the circuit shown in figure XL = XC2 = R, the peak value - Physics - Alternating Current

Question

Solve this:

168     I n   t h e   c i r c u i t   s h
o w n   i n   f i g u r e   X L   =   X C
2   =   R ,   t h e   p e a k   v a l u e
  c u r r e n t   i 0   t h r o u g h   t h e
  a c   s o u r c e   i s

( 1 )     5 V 0 2 R          
                 
                 
                 
                 
      ( 2 )     V 0 2 2 R ( 3 )  
  V 0 2 R              
                 
                 
                 
                 
    ( 4 )     V 0 2 3 R

Manas Pant · Accepted Answer

Dear Student,

As given in the question, XL = Xc/ 2 =R
impedence of parallel LCR circuit,
Z =    11R2+1XL-1Xc2
â€‹  =    11R2+1R-12R2 = 11R2+14R2                                             =    2R5

Now , peak value of current,
I0 = V0Z = V02R5   =5V02R  A
so option (A) is correct

Regards

Solve this: 168 . I n t h e c i r c u i t s h o w n i n f i g u r e X L = X C 2 = R , t h e p e a k v a l u e c u r r e n t i 0 t h r o u g h t h e a . c . s o u r c e i s ( 1 ) 5 V 0 2 R ( 2 ) V 0 2 2 R ( 3 ) V 0 2 R ( 4 ) V 0 2 3 R