Solve this :
17. In the given figure, M is mid-point of AB and DE, whereas N is mid-point of BC and DF.
Show that : EF = AC.
Hiii... here's your answer:
In triangle ABC
M is mid point of AB
N is mid point of BC
Therefore, MN is parallel to AC (by mid point theorem)
And hence MN = 1/2 AC -------1
In triangle DEF
M is mid point of ED
N is mid point of DF
Therefore, MNA is parallel to EF (by mid point theorem)
MN = 1/2 EF--------2
From equation 1 and 2
MN = 1/2 AC = 1/2 AC EF
Therefore, EF =AC
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