Solve this :

2 .   If   D 1 = ab 2 - ac 2 bc 2 a 2 b a 2 c - b 2 c ac - ab ab - bc bc - ac c - b a - c b - a   &   D 2 = 1 1 1 a b c bc ac ab ,   then   D 1 D 2   is   equal   to - ( a )   0                                       ( b )   D 1 2                                         ( c )   D 2 2                                         ( d )   D 2 3
 

Dear Student,
Please find below the solution to the asked query:

We know that Ac=An-1where n is order of square matrix A and Ac is matrix formed by co-factorof each element.Hence for 3×3 matrix, we getAc=A2NowD2=111abcbcacabNow D1=ab2-ac2bc2a2ba2c-b2cac-abab-bcbc-acc-ba-cb-a which is nothing but determinantformed by writing cofactor of reach element of D2=111abcbcacabHenceD1=D22

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