Solve this: 2. In an isolated Li2+. electron jumps from n = 2 to n = 1 . What is the recoil momentum of the ion (in kg- m/s) (1) 5.44 x 10-27 (2) 48.96 x 10-27 (3) 16.32 x 10-27 (4) 8.16 x 10-27 Share with your friends Share 8 Pintu B. answered this Dear Student , Energy of the photon emitted = E = E1-E2E = 13.611-14 eVE = 13.6×0.75 = 10.2 eVMomentum of the emitted photon = P = EC = 10.2×1.6×10-193×108 =5.44×10-27 NsThis momentum of the photon will be the recoiled momentum of the Li2+ atom. Regards -27 View Full Answer