Solve this:

2. The numerical ratio of covering the distance directly proportional to the square of the time. The acceleration of the body is. 
(A) <1      (B) =1           (C) >1           (D)  1

3. A moving body is covering distance directly proportional to the square of the time. The acceleration of the body is. 
(A) increasing          (B) decreasing          (C) zero            (D) constant 

Dear student,

S α t2S=kt2S=ut +0.5at2as distance is proportional to square of time so S=0.5at2or k=0.5aor a is constant

This means acceleration is constant.

So the correct answer is option D
 
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