Solve this: 24. In the given figure, if galvanometer shows null deflection then emf of each cell will be [Total length of wire is 10 m and resistance is 9 Ω ] (1) 9 V (2) 0.9 V (3) 4.5 V (4) 1.8 V Share with your friends Share 21 Shobhit Mittal answered this Dear Student,when it is balanced current through wirei=59+1=0.5 Avoltage drop across the point A and the jockey is the emf of the batteryE=910*2*0.5=0.9 VRegards 10 View Full Answer