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34. A circular coil of diameter of  0.2m with 100 turns, carries a current of 1.2A. Find the magnetic field 
(a) at the centre of coil,
(b) at a point distance 20 cm from centre on the axis.


Dear studentGiven,Radius of circular coil, r=0.2 mNumber of turns, n=100Current, I=1.2 Aa Magnetic field at the centre of the coil B is given byB=μ04π2πnIrB=4π×10-7×100×1.22×0.2B=3.765×10-4 Tb Magnetic field on the axis of the coil is given byB=μ04π2πnIr2r2+x232B=4π×10-74π2π×100×1.2×0.220.12+2232B=2×3.14×10-7×100×1.2×0.040.01+432B=30.144×10-7432        4.014B=30.144×10-78=3.768×10-7 TRegards

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