Solve this: 34. A circular coil of diameter of 0.2m with 100 turns, carries a current of 1.2A. Find the magnetic field (a) at the centre of coil, (b) at a point distance 20 cm from centre on the axis. Share with your friends Share 0 Sanjay Upadhyay answered this Dear studentGiven,Radius of circular coil, r=0.2 mNumber of turns, n=100Current, I=1.2 Aa Magnetic field at the centre of the coil B is given byB=μ04π2πnIr⇒B=4π×10-7×100×1.22×0.2⇒B=3.765×10-4 Tb Magnetic field on the axis of the coil is given byB=μ04π2πnIr2r2+x232⇒B=4π×10-74π2π×100×1.2×0.220.12+2232⇒B=2×3.14×10-7×100×1.2×0.040.01+432⇒B=30.144×10-7432 ∵ 4.01≈4⇒B=30.144×10-78=3.768×10-7 TRegards 0 View Full Answer