Solve this:








6. In Fig. 7.21, AC = AE, AB = AD and $\angle$ BAD = $\angle$ EAC. Show that BC = DE. ​















7. AB is a line segment and P is its mid-point. D and E are ponts  on ttr same side of AB such that 
$\angle$BAD =  $\angle$ABE and ​$\angle$ EPA = $\angle$ DPB
(see Fig. 722). Show that ​
 $\left(\mathrm{i}\right) △\mathrm{DAP}\equiv △\mathrm{EBP}$
(ii) AD= BE