Solve this :


67 .   The   reduction   potential   at   pH = 14   for   the   Cu 2 + / Cu   couple   is   [ Given ,   E ° Cu 2 + / cu = 0 . 34   V ;   K sp   Cu ( OH ) 2 = 1 × 10 - 19 ] ( a )   0 . 34   V ( b )   - 0 . 34   V ( c )   0 . 22   V ( d )   - 0 . 22   V

Dear Student 

As pH = - log H+


So, pOH = 0 
         [OH-]= 100      [Antilog of zero = 100][OH-]= 1          [ As zero power of anything will be 1]
Regards

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