Solve this : 67 . The reduction potential at pH = 14 for the Cu 2 + / Cu couple is [ Given , E ° Cu 2 + / cu = 0 . 34 V ; K sp Cu ( OH ) 2 = 1 × 10 - 19 ] ( a ) 0 . 34 V ( b ) - 0 . 34 V ( c ) 0 . 22 V ( d ) - 0 . 22 V Share with your friends Share 0 Ashish Khanna answered this Dear Student As pH = - log H+ So, pOH = 0 [OH-]= 100 [Antilog of zero = 100][OH-]= 1 [ As zero power of anything will be 1] Regards 0 View Full Answer